FAO of peeps who are good at Maths
Right im a bit retarded when it comes to Maths, Prob somthing to do with me not getting along with the teacher i had for it in comp and i had the same teacher right through
Anyway got a simultainous equation to do and not sure if i got it right, so just want someone to tell me what they got for it
4a+6b=181
4a+2b=100
I know its simple as as the top and bottom both have same number etc but i just want to double check i got the right answer other wise it fooks up a load of other stuff
Anyway got a simultainous equation to do and not sure if i got it right, so just want someone to tell me what they got for it
4a+6b=181
4a+2b=100
I know its simple as as the top and bottom both have same number etc but i just want to double check i got the right answer other wise it fooks up a load of other stuff
Take the binary number on the first and second peramitive of the equasion, then muliply it by 2.974 and take the lowest derogative from the remaning odd numbers.
This will give you the the highest calorific value of the lower number set.
This will give you the the highest calorific value of the lower number set.
Originally Posted by TIFF-C20WTH
Take the binary number on the first and second peramitive of the equasion, then muliply it by 2.974 and take the lowest derogative from the remaning odd numbers.
This will give you the the highest calorific value of the lower number set.
This will give you the the highest calorific value of the lower number set.
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substitute it back into the equation
so use your value of B and multiply it by two (2B), which leaves u with this
4A + 40.5 = 100
4A = 100 - 40.5
4A = 59.5
A = 59.5/4
A = 14.875
HTH
so use your value of B and multiply it by two (2B), which leaves u with this
4A + 40.5 = 100
4A = 100 - 40.5
4A = 59.5
A = 59.5/4
A = 14.875
HTH
Of course
PMSL trying to get back into it.
This gotta be one of the best sites going
Right least i can carry on now with it, cheers peeps though i might be back to ask for some more help
PMSL trying to get back into it. This gotta be one of the best sites going
Right least i can carry on now with it, cheers peeps though i might be back to ask for some more help
Rawli, in your head? Fuck off

Okay, you firstly take the 2nd line from the top
4a + 6b = 181
MINUS
4a + 2b = 100
Leaving 4b = 81
Therefore 1B = 20.25
Now.....take this back to the SECOND equation (easier).
So 4a + 2B = 100
So, 2B os 20.25*2 (40.5).
100 - 40.5 = 4a
Giving A = 14.875
Now, run these two figures through the top equation to chekc they work.
4a + 6b = 181
4a = 59.5
6b = 121.5
So....121.5 + 59.5 = 181
So the values worked out are correct.
Its much easier to follow when written on paper, hope ya can see how i got it mate!
Okay, you firstly take the 2nd line from the top
4a + 6b = 181
MINUS
4a + 2b = 100
Leaving 4b = 81
Therefore 1B = 20.25
Now.....take this back to the SECOND equation (easier).
So 4a + 2B = 100
So, 2B os 20.25*2 (40.5).
100 - 40.5 = 4a
Giving A = 14.875
Now, run these two figures through the top equation to chekc they work.
4a + 6b = 181
4a = 59.5
6b = 121.5
So....121.5 + 59.5 = 181
So the values worked out are correct.
Its much easier to follow when written on paper, hope ya can see how i got it mate!
Rhys,
I did it this way:
4a + 2B = 100
So........ 4a = 100-2b
.... a = 25-1/2b
Which means:
4(25-1/2b) + 6b = 181
Mutiply out.........
100-2b+6b = 181
100+4b = 181
4b = 81
b = 20.25
Then just input that into the other equation:
4a + 40.5 = 100
4a = 59.5
a = 14.875
All I keep seeing is that line at the top of the exam paper that says:
"Don't forget to show ALL your work"
I did it this way:
4a + 2B = 100
So........ 4a = 100-2b
.... a = 25-1/2b
Which means:
4(25-1/2b) + 6b = 181
Mutiply out.........
100-2b+6b = 181
100+4b = 181
4b = 81
b = 20.25
Then just input that into the other equation:
4a + 40.5 = 100
4a = 59.5
a = 14.875
All I keep seeing is that line at the top of the exam paper that says:
"Don't forget to show ALL your work"
I failed A-level maths 
Got a U at AS level lolol....quality, sorted my act out since i been at uni though, can even do calculus
*just* LOL. It being an engineering degree theres crap loads of maths formulas etc, so im getting there now. 
Rich, indeed. In that case you multiply everything up till you have a common factor, and then add, or subtratc whichever

Got a U at AS level lolol....quality, sorted my act out since i been at uni though, can even do calculus
*just* LOL. It being an engineering degree theres crap loads of maths formulas etc, so im getting there now. Rich, indeed. In that case you multiply everything up till you have a common factor, and then add, or subtratc whichever
Cheers peeps, Maths is my week point on my course at uni, somthing i really need to sit down and think about.
Trying to do this course work as its gotta be in for next Friday
Trying to do this course work as its gotta be in for next Friday
Originally Posted by PhilM
I failed A-level maths 
Got a U at AS level lolol....quality, sorted my act out since i been at uni though, can even do calculus
*just* LOL. It being an engineering degree theres crap loads of maths formulas etc, so im getting there now. 

Got a U at AS level lolol....quality, sorted my act out since i been at uni though, can even do calculus
*just* LOL. It being an engineering degree theres crap loads of maths formulas etc, so im getting there now. tell me about it, im doin a similar course remember lol
i got an A at AS
found my reports from AS saying that i was a good student on for A/B at A level
got C and 2Es
Cheers Rich mate that would be cool
Will let u know if i get stuck on anything more.
lol i didnt take A level Maths, infact i got a D for GCSE in it. Just goes to show how much im learning at the moment agian now. Still all good fun though
Will let u know if i get stuck on anything more.lol i didnt take A level Maths, infact i got a D for GCSE in it. Just goes to show how much im learning at the moment agian now. Still all good fun though
If your ever unsure to whether its correct,
if u put the values that you have calculated into either (or both for piece of mind) of the equations the answer will always be correct. this is always good as it means you cant be wrong, Most of the marks awarded for simulataneous equations is for the working out, as the answer can simple at times
if u put the values that you have calculated into either (or both for piece of mind) of the equations the answer will always be correct. this is always good as it means you cant be wrong, Most of the marks awarded for simulataneous equations is for the working out, as the answer can simple at times
4x + 6y = 230 --> [1]
1x + 1y = 40 --> [2]
Multiply [2] by 4, to get an equal coefficient of x:
4x + 6y = 230
4x + 4y = 160
Subtract:
2y = 70 --> y = 35
Substitute into [1]:
4x + 6(35) = 230 --> 4x + 210 = 230 --> 4x = 230 -210 = 20 --> x = 5
I still remember it, despite it being last millennium that I did A-Level Maths!
1x + 1y = 40 --> [2]
Multiply [2] by 4, to get an equal coefficient of x:
4x + 6y = 230
4x + 4y = 160
Subtract:
2y = 70 --> y = 35
Substitute into [1]:
4x + 6(35) = 230 --> 4x + 210 = 230 --> 4x = 230 -210 = 20 --> x = 5
I still remember it, despite it being last millennium that I did A-Level Maths!
LOL aint Maths great
To be fair its quite good when u get into it, but if u get stuck u fookin get stuck. Not like when your wrighting a report u can talk bollocks around it
To be fair its quite good when u get into it, but if u get stuck u fookin get stuck. Not like when your wrighting a report u can talk bollocks around it
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