Wots the max Injector time for different Rpm's ?
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PassionFord Post Whore!!
Joined: Oct 2003
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From: S/E Kent, Thanet
on a Cossie running piper 509 (similar to bd16) inlet cam, with 264 duration.
i'm tryin to find out the maxium time available (for injector openin) at all rpm sites between 1000 to 8500 rpm.
as tryin to understand why i'm havin problems on my s8.
Cheers Danny
i'm tryin to find out the maxium time available (for injector openin) at all rpm sites between 1000 to 8500 rpm.
as tryin to understand why i'm havin problems on my s8.
Cheers Danny
have you got the opening duration of a bd16 cam in degrees then? if so, just convert that into time over the range of engine speeds. if not, you need it.
does this help?
https://passionford.com/forum/viewtopic.php?t=157347
does this help?
https://passionford.com/forum/viewtopic.php?t=157347
Originally Posted by Stu @ M Developments
The amount of fuel we can inject is heavily reliant on one main factor, and that factor is the "Induction Stroke Time Base" This, in more english terms is simply the amount of time we have to inject the fuel whilst the inlet valve is actually OPEN. So imagine we have, on a theoretical engine, an intake valve opening time of 16MS at 7000rpm. You are revlimited to 7100, so we dont need to concern ourselves with higher rpm. OK? This 16MS is also subject to camshaft duration normally, a longer cam will give a longer opening time. So, given this info, we also know our peak power requirement is going to be 300bhp. Our chosen fuel pressure for the system, based on all requirements (See recent essay. lol) is 3.5bar. So we need to now select an injector, that can supply enough fuel in 16MS for its share of 300bhp (4 cylinders = 75bhp each) with a pressure of 3.5bar but pushing them no harder than 70% for injector reliability.
So cool, weve chosen our injector, the engine is dynod or mapped and weve got total success, 300bhp at 7000rpm, the fuel system and the engine is totally within tolerances. Game Over, home in time for tea. Or is it..
Our intake valve thats only open for 16ms (pure example) at 7000rpm is in fact open for 32MS at 3500rpm isnt it? (7000/2 so 16x2)) The same injector that can only sustain the fuel for 2bar of boost and 300bhp at 7000rpm is PERFECTLY capable of supplying the fuel for a "Theoretical" 3bar+ of boost at 3500rpm as the fuel has twice as long to get into the engine so we can hold the injector open for twice as long if need be or possible.
In reality, we would only open the injector in this theoretical engine spec for 25% longer to keep within the absolute max constraints of 95% injector duty cycle and even then, 95% is only for peaks such as described and NEVER used at high rpm. But im sure your now getting the picture as to why engines CAN run a nice big peak, but its not safe to hold the boost that high.
So cool, weve chosen our injector, the engine is dynod or mapped and weve got total success, 300bhp at 7000rpm, the fuel system and the engine is totally within tolerances. Game Over, home in time for tea. Or is it..
Our intake valve thats only open for 16ms (pure example) at 7000rpm is in fact open for 32MS at 3500rpm isnt it? (7000/2 so 16x2)) The same injector that can only sustain the fuel for 2bar of boost and 300bhp at 7000rpm is PERFECTLY capable of supplying the fuel for a "Theoretical" 3bar+ of boost at 3500rpm as the fuel has twice as long to get into the engine so we can hold the injector open for twice as long if need be or possible.
In reality, we would only open the injector in this theoretical engine spec for 25% longer to keep within the absolute max constraints of 95% injector duty cycle and even then, 95% is only for peaks such as described and NEVER used at high rpm. But im sure your now getting the picture as to why engines CAN run a nice big peak, but its not safe to hold the boost that high.
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PassionFord Post Whore!!
Joined: Oct 2003
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From: S/E Kent, Thanet
so is there a equation to work it out?
i take it 1000 milliseconds = 1 second,
so 1 minute = 60000 m/s.
and to 1 rpm = 264 inlet open duration = inlet vavle open for 73.33% of total cam duration per rpm.
So at 3000rpm =
60000 / 3000 = 20 m/s X 73.33% = 14.67 m/s max fuel injector open time???????
so at 7500 rpm =
60000 / 7500 = 8 m/s X 73.33% = 5.87 m/s max fuel injector open time?
Does that look right?
Edited 6/12/05 cos had a long day yesterday
i take it 1000 milliseconds = 1 second,
so 1 minute = 60000 m/s.
and to 1 rpm = 264 inlet open duration = inlet vavle open for 73.33% of total cam duration per rpm.
So at 3000rpm =
60000 / 3000 = 20 m/s X 73.33% = 14.67 m/s max fuel injector open time???????
so at 7500 rpm =
60000 / 7500 = 8 m/s X 73.33% = 5.87 m/s max fuel injector open time?
Does that look right?
Edited 6/12/05 cos had a long day yesterday
don't think that's quite right.
cams turn at half the crank speed, so for every 1 crank revolution the inlet cam turns 180 degrees.
when you get the right time, you don't multiply it by 4.
hth a bit, and back to the maths book
cams turn at half the crank speed, so for every 1 crank revolution the inlet cam turns 180 degrees.
when you get the right time, you don't multiply it by 4.
hth a bit, and back to the maths book
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are you sure that a duration of 264 means that the inlet valve is open for 264 degrees out of one cam rotation? that's 528 degress out of the 720 degres of 2 crank revolutions? how can you fit in 4 strokes if the inlet valve is open for that long?
maybe it means 264 degrees of one crank rotation (so 132 degrees of cam rotation)?
i don't know for sure, i'm just trying to learn along with you.
maybe this diagram, found by Gareth T on this post helps?
maybe it means 264 degrees of one crank rotation (so 132 degrees of cam rotation)?
i don't know for sure, i'm just trying to learn along with you.
maybe this diagram, found by Gareth T on this post helps?
How long the inlet is open is not that important, it´s the time between cycles that is important. And you just need to know how much time you have at your maximum rpm. At half the rpm you have twice the time, but it´s not likely that your engine can handle twice the amount of fuel just because you have the time to inject it.
It´s 60000ms in a minute and that divided by the max rpm will be:
60000 / 8500 = 7.06ms between tdc and since it´s a 4-cycle you get twice the time. That equals 14.12ms @ 8500rpm
The reason that it´s not that important to inject while the intake is open seems logic when doing some more math, The intake valve will open and close nearly 71 times every sec @ 8500rpm. The fuel will never have the time to stop by the valvehead and "wait" for it to open.
It´s 60000ms in a minute and that divided by the max rpm will be:
60000 / 8500 = 7.06ms between tdc and since it´s a 4-cycle you get twice the time. That equals 14.12ms @ 8500rpm
The reason that it´s not that important to inject while the intake is open seems logic when doing some more math, The intake valve will open and close nearly 71 times every sec @ 8500rpm. The fuel will never have the time to stop by the valvehead and "wait" for it to open.
come on dave, be fair, there's clever in more ways than being able to read and write properly.
i'd say building a 4x4 cosworth powered fiesta and turboe'd xr2 and having a go at mapping them yourself is quite clever
i'd say building a 4x4 cosworth powered fiesta and turboe'd xr2 and having a go at mapping them yourself is quite clever
I don´t think this is a realistic option for most people.
The inlet only opens every other crank rev, so then you have 7.06ms between tdc@8500rpm
One revolution is 360degrees, inlet is open 264degrees of that. So:
7.06 / 360 * 264 = 5.18ms@8500rpm
This means you need LARGE injectors to get enough fuel for making decent power.
The inlet only opens every other crank rev, so then you have 7.06ms between tdc@8500rpm
One revolution is 360degrees, inlet is open 264degrees of that. So:
7.06 / 360 * 264 = 5.18ms@8500rpm
This means you need LARGE injectors to get enough fuel for making decent power.
Originally Posted by SECS
LOL at all those guesses (YBP is close)
Will post up the definitive answer later when I have had my tea
Will post up the definitive answer later when I have had my tea
Originally Posted by YBP
This means you need LARGE injectors to get enough fuel for making decent power.
Nick, I guess the most obvious benefit firing the injector when the valve is open, is that the incoming air helps to atomise the fuel better = better burn. If you fire before the valve opens, then you could risk fuel pooling/poor atomisation.
Originally Posted by foreigneRS
Originally Posted by SECS
LOL at all those guesses (YBP is close)
Will post up the definitive answer later when I have had my tea
Will post up the definitive answer later when I have had my tea

Sorry, didnt mean to diss anyone.
I didnt see Stu's explaination above so I dont need to go into full detail
as he has done the hard work.
Generally the equation I use ( I have simplified it so you can all follow)
A=RPM/60
calculate crank rotations per second
B=1/A
calculate 1 rev time in seconds
C=B*2
allow for 2 crank cycles
D=C*1000
convert to milliseconds
E=D * 0.90
only use 90% duty cycle (or what even you deem correct)
The value in E is the final maximum allowable injection time in millisconds.
=============================
When talking about SEQUENTIAL injection as on cossies....
Fuel injection point (I.E the crank rotation degrees an injector starts to inject)
is generally only critical at low speeds as you inject MOST of the fuel on a CLOSED
inlet valve just before it begins to open.
The reason is, 1, it cools the valve and 2, the inrush of air mixes the fuel
better than
injecting the whole lot while filling the cylinder.
This applies to low loads and low rpm's only generally.
So its NOT just injection duration thats critical but WHEN it injects.
This is because the slow moving air at low rpm will cause the fuel to drop
out or the mixture if not kept moving.
However, at high rpm, (above >2500 rpm usually) the injection point is advanced
as the average air speed does not change much mixing the air/fuel better.
(on a cossie usually about +90 degrees every 1000 rpm till 5500 rpm)
So you can see, the map is NOT the only thing that matters.
At high rpm and/or high loads, the timing of the inlet valve becomes LESS
critical as generally all fuel in the inlet port will get into the cylinder and
is mixed nicely due to the high speeds and squish effect of the cylinder design.
===============================================
Ok, now back to Dannys original "problem" with the S8.
He complained about getting error code 31.
This error is set when the available fuel time based on the current rpm
is exceeded. The error code also cuts the power to the injectors to prevent
the engine melting. The reason is the map is telling the injectors to open
MORE than the time available. This means there COULD be NOT enough
fuel to match the air, the result - melt down.
I have set this to a figure of 95% of the injection duty cycle in the ecu
software that CANNOT be changed by the mapper only me.
This is a safety feature and therefore protects the user and myself from
destroyed engines and all the sh*t that may go with it.
On Dannys car, he has 8 injectors and a turbo that spools up faster than
ima taking the piss out of me
There may be a possible scenario where the ecu software estimates the rate
of rise of the rpm and may be prematurely causing this fault.
Rather this way than the reverse from an engine safety point of view.
I have been unable to reproduce the fault on my engine simulator YET.
Danny,
Could you please tell me exactly at what rpm this fault occurs
and what boost you think it happens at.?????
You did tell me by email but have lost all my emails since then in a
hard disk crash.
Simon:
https://passionford.com/forum/viewtopic.php?p=2287746
Originally Posted by fiesta cossie
cheers,
has he had any problems? so he's runnin a good 390 - 410 bhp?
but as my fault is that fuel injector time is excedin ignition timing ( maxxed out)
it does it at anything more than 27-8 psi boost, at any rev's even at 4000rpm and 7000rpm.
has he had any problems? so he's runnin a good 390 - 410 bhp?
but as my fault is that fuel injector time is excedin ignition timing ( maxxed out)
it does it at anything more than 27-8 psi boost, at any rev's even at 4000rpm and 7000rpm.
I have found the problem !!! It was a software issue
Never shown up before as most people that run 8 injectors, run laggy T4's
that dont generate boost until the rev limit
I was correct, the ecu is predicting the rev rate rise too fast.
I am just modifying the software, can you send me email address
to simon@s8ecu.co.uk and I will send the update programs within an hour.
Never shown up before as most people that run 8 injectors, run laggy T4's
that dont generate boost until the rev limit
I was correct, the ecu is predicting the rev rate rise too fast.
I am just modifying the software, can you send me email address
to simon@s8ecu.co.uk and I will send the update programs within an hour.
Thread Starter
PassionFord Post Whore!!
Joined: Oct 2003
Posts: 4,775
Likes: 0
From: S/E Kent, Thanet
Originally Posted by SECS
I have found the problem !!! It was a software issue
Never shown up before as most people that run 8 injectors, run laggy T4's
that dont generate boost until the rev limit
I was correct, the ecu is predicting the rev rate rise too fast.
I am just modifying the software, can you send me email address
to simon@s8ecu.co.uk and I will send the update programs within an hour.
Never shown up before as most people that run 8 injectors, run laggy T4's
that dont generate boost until the rev limit
I was correct, the ecu is predicting the rev rate rise too fast.
I am just modifying the software, can you send me email address
to simon@s8ecu.co.uk and I will send the update programs within an hour.
Sounds promising
emailed you. either wise its dannycampion@hotmail.com
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