Just find out what rpm it produces the BHP at and back calc the torque....

Torque is the twisting force. In our case created by the combusiton process, pushing the piston and rod down, twisting the crank.

Basically, the way I explained it myself back in the day is as follows.

Torque, the force produced by one cylinder firing once. At any given point in RPM and conditions, a cylinder volume with the right mixture will create the most power (right ignition timing etc) at a set RPM.

Lets say our little basic 100bhp polo (for random example). It will probably produce peak torque about 3,500 rpm. That is the engine rotation speed that the engine is being its most efficient (for numerous reasons).

As the RPM of the car rises above that peak efficiency moment, the torque produced by that cylinder will slowly reduce. IN my simplified view, it was just the engine moving out of its most efficient speed (ie at perfect peak torque, the engine might get 0.1 second at our example of 3,500rpm to fill the cylinder, because the inlet valve is open for .1 seconds. If you do twice the rpm, the cylinder only gets 0.05 seconds till fill, therefore it probably will not fill as efficiently (that my assumption at the time, when i was trying to get my head round it all, it will have quite a bit to do with a multiple of other variables like combustion chamber shape, ignition timing and the natural burn time of the correct fuel air mixture, inlet valve lift, inlet to exhaust valve ratios and so on but that is too complex for this and for me when I was first thinking about it all.

SO - bhp, is basically how many of those small explosions happen every second.

Obviously 100 small explosions at 95% of peak power (peak torque), gives u more go than 1 explosion at 100% of peak power. Therefore "torque" is not the be all and end all. You need a power band that is of a size that suits the conditions/situation u are using the engine.

Need to go to bed - will look at this explanation tomorrow and make sure it makes sense.

RW