A good one for the mathematic gurus here,

went to the pod in ths ST today and acheived a 16.001s @ 88.07 mph. (The track was soooo slippy and i have a pb of 15.725 at york raceway.)

anyway..... my friend pipped me with a faster time of 15.984s.

What i want to know is...........

what is the distance he beat me by? assuming the same terminal velocity etc.

Cheers to whom ever can work this out,

 

I take it you were one of the 2 ST's that kept racing

If this hasn't been done already i'll work it out in the morning for ya .

 

time diff 0,017s
speed ca 88,1mph=141,75km/h=39,375m/s
39,375m/s*0,017s=0,669m
You was beeten by ca 67cm or 26,4in
every thing is ca, but its close

 

as above - well done that man!

 

certainly well done.

next time ill rig the car up with sum machanism which will spring out infront giving me the extra length etc etc lol........... err no lol.

another go with a stickier strip should be fun

 

think that distance will only be correct if you both broke the start beam at the same time, i.e. had the same reaction time, as the timing only starts from when you break that first beam
i.e. i have seen the car with a slower time cross the line first because it got away much quicker
hope that makes sense..?

 

"ask any racer, any real racer....it dont matter if you win by an inch or a mile!"


sorry