Originally Posted by
tabetha
Resistor total value in parallel is a bit more complicated to work out than series, where it's all just added together to find the total.
To find the resistance of parallel resistors it is Rt= R1XR2XR3/R1+R2+R3.
To do it this way would be a over complicated way, you could instead use a 10W wire wound resistor of say 47ohm, which is a VERY common value, in practice there won't be a problem between 48ohm and 47ohm, a 10W wire wound will carry roughly 3/4 amps, is this enough ?
If not these can be bunched if needed ?
tabetha
it needs to carry 6 amps, thats 1 amp per injector. But if your equation is correct they would have a total resistance of 16 ohms in parralel? four resistor packs at 6 ohms each. 4x4x4x4 (256) divided by 4+4+4+4 (16)= 16 ohms total, not enough.
if i put them in series they may over heat?