so am i correct with my maths: using V=IR therefore I=V/R if my injectors are 4 ohm and my ressistor pack is 8 ohm then the current draw (with 12 ohms) will be 12ohms/12 volts= 1amp?
Which is the equivelent draw that a single 12 ohm injector would have. The 4 ohm resistors on thier own would be 12/4= 3 amps each! too much IMO, will the low impedance injectors still function as they should?