Partial Fractions

Okay, here goes......

7x+6/(x-2)(x+3) = A/((x-2) +B/(x+3)

Mutliply it out so that you end up with:

7x+6 = A(x+3) + B(x-2)

Then if x=2

20 = 5A, so A = 4

Then if x=3

-15 = -5B, so B = 3

Therefore:

7x+6/(x-2)(x+3) = 4/(x-2) + 3/(x+3) expressed as a partial fraction.

9 years since I've done that, and I still enjoyed it - what a geek!